What is the derivative of tan^5(x)? | Socratic
Mar 20, 2018 · Explanation: Let, y = tan5x = (tanx)5. We take, y = u5, where, u = tanx. ⇒ dy du = 5u4 and du dx = sec2x. Applying chain rule. dy dx = dy du ⋅ du dx. ⇒ dy dx = 5u4 ⋅ sec2x.
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